小学数学太难了系列2
在乘积\(2018\cdots 2018\times 15151414\cdots 0707\)的十进制表示中，共有多少个奇数？
A question you can ask to chiese primary school students, how many odd digits are there in the product \(2018\cdots 2018\times 15151414\cdots 0707\), where the first factor is 2018 repeated 28 times.
会长的话
\(2018\times 1515\cdots0707=9999\times c,\ \ c\in \mathbb{Z}\)， 根据杯中兔同志的计算，答案是71.